WebThese were calculated for depths of 0.005 cm. , 1 c m . and 5.0 cm. using the coefficients of Aschkinass. It is clear that 1 c m . completely absorbs radiation X > 1.4 ¡i, and that 10 c m . would absorb X > 1.0 ¡x. In the region 1.0 X > 0.7 ¡i. it is difficult to calculate in advance the transmission of a glass-bottomed tray. The presence or ... Webhow our equation solver works Enter your math expression x2 − 2x + 1 = 3x − 5 Get Chegg Math Solver $9.95 per month (cancel anytime). See details Example math equations: Pre Algebra Algebra Pre Calculus Calculus Linear Algebra Arithmetic Simplify: (6+3)\cdot (10-7) (6+3)⋅(10 −7) See answer › Negative numbers Simplify:
Evaluate using suitable identities. 98 x 103 - Sarthaks
WebQuestion Evaluate 102×98 using suitable standard identity. Medium Solution Verified by Toppr Using the identity (x+a)(x+b) = x 2+(a+b)x+ab Writing 102 as 100+2 and 98 as 100−2 Hence (100+2)(100−2) = 100 2+[2+(−2)]100+(2)(−2) = 10000+(0)100−4 = 9996 The answer is 9996 Was this answer helpful? 0 0 Similar questions Evaluate: 53×55 Medium WebMar 22, 2024 · Transcript. Example 17 Evaluate 105 × 106 without multiplying directly. 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab ... papertown julian smith
Evaluate using suitable identities. 101 x 103 - Sarthaks
WebEvaluate: 98 × 103. Solution: Given, 98 × 103 = (100 - 2) (100 + 3) Using standard identity: (x + a) (x + b) = x² + (a + b)x + ab. Here x = 100, a = -2 and b = 3 ... WebAug 6, 2024 · Identity : ( x + a ) ( x + b ) = x² + ( a + b ) x + ab, 95 × 96 = ( 100 - 5 ) ( 100 - 4 ) = ( 100 )² + ( -5 - 4 ) 100 + ( -5 ) ( -4 ) = 1000 - 900 + 20 = 9, 120 Cheers! wlcm .. :) Thanks! ha ....ye clear hai Advertisement Advertisement WebOct 1, 2014 · (103) whole cube. To find: The value of (103) whole cube. Solution: To answer this question, first of all, we should know about one of the algebraic identities which is Now, proceeding to the solution, As we know that 103 can be written as the sum of 100 and 3. So, By using the above algebraic identity, we have, On solving the above, we get papertown dairy bar spring grove menu